0.0048x^2-2.47x+300=0

Solution for 0.0048x^2-2.47x+300=0 equation:

0.0048x^2-2.47x+300=0

a = 0.0048; b = -2.47; c = +300;
Δ = b2-4ac
Δ = -2.472-4·0.0048·300
Δ = 0.3409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.47)-\sqrt{0.3409}}{2*0.0048}=\frac{2.47-\sqrt{0.3409}}{0.0096}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.47)+\sqrt{0.3409}}{2*0.0048}=\frac{2.47+\sqrt{0.3409}}{0.0096}
$